Question

1,(03) : 0,(6) - (1/3)^2 x (1/9)^-2
DAU COROANA + 20 PCT

Answer 1

$1,(03):0,(6)-(\frac{1}{3})^{2}*(\frac{1}{9})^{-2}=?\\ \\ //->1,(03)=\frac{103-1}{99}=\frac{102}{99}=\frac{34}{33}.\\ \\ //->0,(6)=\frac{6}{9}=\frac{2}{3}.\\ \\ //->(\frac{1}{3})^{2}=\frac{1}{9}.\\ \\ //->(\frac{1}{9})^{-2}=9^{2}=81.\\ \\ \frac{34}{33}:\frac{2}{3}-\frac{1}{9}*81=\frac{34}{33}*\frac{3}{2}-9=\frac{17}{11}-9=\frac{17-99}{11}=\frac{-82}{11}=-\frac{82}{11}.$

/rfd