Question

1 ) 1+3×{[17+5×[730-6×(x-3×32)]}+1=2003

2 ) [(203×4-207):5+240×3-769-3121:12)]×x=1000

Answer 1

1)
1+3×{[17+5×[730-6×(x-3×32)]}+1=2003

1+3×{[17+5×[730-6×(x-96)]} = 2003-1=2002

3×{[17+5×[730-6×(x-96)]} = 2002-1 = 2001

17+5×[730-6×(x-96)] = 2001 : 3 = 667

5×[730-6×(x-96)] = 667 - 17 =650

730 - 6×(x-96) = 650:5 = 130

6×(x-96) = 730 - 130 = 600

x - 96 = 600 : 6 = 100

x = 100 + 96

x = 196

Al doilea exercitiu nu este scris corect in totalitate:
o paranteza mica lipseste si 3121:12 = da cu rest.