Question

[1,1 (6)+1 intreg si 1 pe 4 : 0, (3)]-(2 -4 pe 3) totul la puterea 2

Answer 1

[1,1 (6)+1 intreg si 1/4 : 0, (3)]-(2 -4/3)²=
=[(116-11)/90+5/4 : 3/9]-(2/3)²=
=(105/90+5/4 :1/3)-4/9=
=(7/6+5/4 ×3)-4/9=
=(7/6+15/4)-4/9=
=(14+45)/12-4/9=
=59/12-4/9=
=(177-16)/36=
=161/36=4,47(2)