Question

1. {12[7(3^3-2^4)-2]-1}-75 .
2. Determina x astfel incat 21x + 15 =233 .
3. Sa se scrie toate numerele prime mai mici decat 30 .

Answer 1

1. Rezolvare
{12[7(3^3-2^4)-2]-1}-75=
3^3=3×3×3=9×3=27
2^4=2×2×2×2=4×2×2=8×2=16
{12[7(27-16)-2]-1}-75=
[12(7×11-2)-1]-75=
[12(77-2)-1]-75=
(12×75-1)-75=
(900-1)-75=
899-75=
824


21x + 15 = 233
21x = 233-15
21x = 218 》cred ca ai scris

1,7,11,13,19,21,23,29,