Question

1) {14+3•[15+5•(200-18•10)]}•2-483
2)ce numar natural impartit la 37da catul 14 si restul31?

Answer 1

{ 14+3×[15+5×20]}×2-483= {14+3×115}×2-483= {14+345}×2-483=359×2-483=718-483= 235 2)a:37=14r31 a=37×14+31 a=549

Answer 2

1) {14+3•[15+5•(200-18•10)]}•2-483
{14+3•[15+5•(200-180)]}•2-483=
[14+3•(15+5•20)]•2-483=
[14+3•(15+100)]•2-483=
(14+3•115)•2-483=
(14+345)•2-483=
359•2-483=
718-483=235