Question

(1/2-1/6:1/3)^2009 va rooog

Answer 1

[1/2-1/6·3]²⁰⁰⁹=[1/2-3/6]²⁰⁰⁹=[1/2-1/2]²⁰⁰⁹=0²⁰⁰⁹=0;

Answer 2

$( \frac{1}{2} - \frac{1}{6} : \frac{1}{3} )^2^0^0^9=( \frac{1}{2} - \frac{1}{2} )^2^0^0^9=0^2^0^0^9=0$