Question

1+2^2×(3^2:9-1) ×8+2008^0

Answer 1

$1 + 2 {}^{2} \times (3 {}^{2} \div 9 - 1) \times 8 + 2008 {}^{0}$
1+4x(9÷9-1)x8+1
1+4x(1-1)x8+1
1+4x0x8+1
1+0x8+1
1+0+1
1+1
2