Question

1+2×(3^2:9-1):3+100^0=

Answer 1

$1 + 2 \times ( {3}^{2} \div 9 - 1) \div 3 + {100}^{0}$

$= 1 + 2 \times (9 \div 9 - 1) \div 3 + 1$

$= 1 + 2 \times (1 - 1) \div 3 + 1$

$= 1 + 2 \times 0 \div 3 + 1$

$= 1 + 0 \div 3 + 1$

$= 1 + 0 + 1$

$= 2$