Question

1+{2-[3+(x+4):5]:6}*7=8​

Answer 1

Răspuns: $\red{\bf \underline{x = 11}}$

Explicație pas cu pas:

Am folosit metoda mersului invers

$\bf 1+\{2-[3+(x+4):5]:6\}\cdot7=8$

$\bf \{2-[3+(x+4):5]:6\}\cdot7=8-1$

$\bf \{2-[3+(x+4):5]:6\}\cdot7=7~~~~\bigg|:7$

$\bf 2-[3+(x+4):5]:6=1~~~~\bigg|\cdot 6$

$\bf 2\cdot 6-[3+(x+4):5]=6$

$\bf 12-[3+(x+4):5]=6$

$\bf 12=6+[3+(x+4):5]$

$\bf 12=6+3+(x+4):5$

$\bf 12=9+(x+4):5$

$\bf 12-9=(x+4):5$

$\bf \bf 3=(x+4):5~~~~\bigg|\cdot 5$

$\bf 3\cdot 5=(x+4)$

$\bf 15=x+4$

$\bf x=15-4$

$\red{\bf \underline{x = 11}}$

==pav38==

Baftă multă !