Question

1.2pe5 . 4pe3
2.12pe25 . 20pe27
3.2pe3 . 6pe5 - 0,05
4.5pe4 . 9pe20 - 1pe16
5.(3pe7-3pe69)
6.(3,7-3,69) . [1+0,(01) -1pe99
7.(1 1pe6 . 9-9 1pe4) . (0,15 + 0,2 . 0,15) + 17pe16

Answer 1

 $1) \frac{2}{5}\cdot \frac{4}{3}= \frac{2\cdot4}{5\cdot3} = \frac{8}{15} \\ \\ 2) \frac{12}{25}\cdot \frac{20}{27}= \frac{4\cdot4}{5\cdot9} = \frac{16}{45} \\ \\ 3) \frac{2}{3}\cdot \frac{6}{5}- \frac{5}{100}= \frac{4}{5}- \frac{5}{100}= \frac{80-5}{100}= \frac{75}{100}= \frac{15}{20} \\ \\4) \frac{5}{4}\cdot \frac{9}{4\cdot5}- \frac{1}{4\cdot4}= \frac{45-5}{80}= \frac{40}{80}= \frac{1}{2}$
$5) \frac{3}{7}- \frac{3}{69}= \frac{3\cdot23\cdot3-3\cdot7}{3\cdot23\cdot7}= \frac{207-21}{483}= \frac{186}{483}$
$6) (3,7-3,69)\cdot[1+0,(01 )- \frac{1}{99}= ; 0,(01)= \frac{1}{99} \\ \\ 0,01\cdot[1+ \frac{1}{99}- \frac{1}{99}]= 0,01$

$7) 1\frac{1}{6}= \frac{7}{6};9 \frac{1}{4}= \frac{37}{4}$
$0,15= \frac{15}{100}= \frac{3}{20} ; 0,2\cdot0,15=0,03$
$(\frac{7}{6}\cdot \frac{37}{4})( \frac{3}{20}+ \frac{3}{100})+ \frac{17}{16}=$
$\frac{259}{24}\cdot \frac{18}{100}+ \frac{17}{16} =$