Question

1) 2x+4x+6x+10x-13 <x+3x+5x+7x+9x+12=
2) a
Aflati numerele naturale x si y stiind ca:
a) (x+1)×(y+2)=42
b) (x+3)×(y+5)=72
3) Determinați x si y:
a) 7×cu cu bara deasupra +yx cu bara deasupra = xyyx cu bara deasupra :11+1
b) 9× xx cu bara deasupra =xxx cu bara deasupra : 37 +480



UUUURRRRGGGGGEEEENNNNTTTTAAAA!!!!!!!!
DAU OROANA!!!!!!

Answer 1

1) 22x-13<25x+12
22x-1<25x
X=1

2) (x+1) * (y+2)=42
(x+3) * (y+5)=72
X*y+2x+y+2=42
X*y+5x+3y+15=72

X*y+5x+3y=57
X*y+2x+y=40
Le scădem
3x+2y=13
(x,y)={(1,5),(3,2)}

3)
A) 70+x+70y+x= (1001x + 110y) :11+1
69+2x+70y= 91x + 10y
69+60y=89x

*=ori
Atat știu! Sper ca te-am ajutat!