Question

(1/3-1)la a 2 a:[0, (6) la a 5a]

Answer 1

[tex]\it \left(\dfrac{1}{3}-1\right)^2 : [0,(6)]^5= \left(\dfrac{1}{3}-\dfrac{3}{3}\right)^2 : \left(\dfrac{6}{9}\right)^5= \left(\dfrac{-2}{3}\right)^2 : \left(\dfrac{2}{3}\right)^5= \\\;\\ \\\;\\ = \left(\dfrac{2}{3}\right)^2 : \left(\dfrac{2}{3}\right)^5= \left(\dfrac{2}{3}\right)^{2-5}= \left(\dfrac{2}{3}\right)^{-3}= \left(\dfrac{3}{2}\right)^{3}= \dfrac{27}{8} [/tex]

Answer 2

Am scris pe foaie...
Sper ca e corect