Question

1) (3 intregi 2/6 +1 intreg 5/7) ori 1 intreg 2/3)
2) -2x+8-12= -20 in Z
3) (3intregi 2/8+1 intreg 5/6) impartit 1/12
4) 5x-30+10=-45

Answer 1

1. (3 si 2/6 + 1 si 5/7) * 1 si 2/3 = (⁷⁾20/6 + ⁶⁾12/7) * 5/3 = (140/42 + 72/42) * 5/3 =

212/42 * 5/3 = 1060/126 = 530/63

2. - 2x + 8 - 12 = - 20

- 2x = - 20 + 4

x = 16/2

x = 8

3. (3 si 2/8 + 1 si 5/6) :1/12 = (³⁾26/8 + ⁴⁾11/6) * 12 = (78/24 + 44/24) * 12 = 122/24 *

* 12 = 122/2 = 61

4. 5x - 30 + 10 = - 45

5x = - 45 + 20

5x = - 25

x = - 25/5

x = - 5