Question

1. (4x+5)*(2x-3)-(8x la a doua+9x-15)=
2.(5√6+√3)*(4√2-3√3)=
3.(-5 supra 4 x2)*(8 supra 10 x3)-(8 supra 3 x8)-(-4 supra 9 x3)=

Answer 1

o poza nu poti sa facisi tu vedem mai bine ca nu se prea inteege

Answer 2

1) 8x²-12x+10x-15-8x²-9x+15=-11x

2) 20√12-15√18+4√6-9=20×2√3-15×3√2+4√6-9= 40√3-45√2+4√6-9

3)(-5/2)×(4/5×8)-64/3-(-4/3)=(-5/2)×32/5-64/3+4/3=-16-64/3+4/3=

          /-48-64+4/3=-108/3=-36

/bara inseamna supra/ bafta.