Question

1,625g metal divalent reactioneaza cu o solutie de acid clorhidric 30% rezultand 0.05g hidrogen. afla concentratia procentuala a solutiei obtinuta prin dizolvarea sarii rezultate in 10g apa.

Answer 1

Din nou, notam metalul - M
A g...............A+71....2g
M + 2HCl -> MCl2 + H2
1,625g...........x=?....0,05g
A=1,625*2/0,05=65g => M-Zn
x=1,625*(65+71)/65=1,625*136/65=3,4g clorura de zinc
ms=3,4+10=13,4g solutie ZnCl2
c=md*100/ms=3,4*100/13,4=340/13,4=25,37%