Question

(1/√8 + 1/√32 - 1√2) :√2/2

Answer 1

Daca HDAlex a vrut sa scrie asa
$\left(\dfrac{1}{\sqrt8}+\dfrac{1}{\sqrt{32}}-\sqrt2\right):\dfrac{\sqrt2}{2}=$, atunci rezolvarea este:
$=\left(\dfrac{1}{2\sqrt2}+\dfrac{1}{4\sqrt2}-\sqrt2\right)\cdot\sqrt2=\dfrac12+\dfrac14-2=\dfrac{2+1-8}{4}=-\dfrac54$

Daca a vrut sa scrie asa:
$\left(\dfrac{1}{\sqrt8}+\dfrac{1}{\sqrt{32}}-\dfrac{1}{\sqrt2}\right):\dfrac{\sqrt2}{2}=$
atunci rezolvarea este:
$=\left(\dfrac{1}{2\sqrt2}+\dfrac{1}{4\sqrt2}-\dfrac{1}{\sqrt2}\right)\cdot\sqrt2=\dfrac12+\dfrac14-1=\dfrac{2+1-4}{4}=-\dfrac14$