Question

1-(9/8)^6 * (2/3)^12
(4/9)^10 *[(27/8)ˆ3 ]ˆ2 + (1/7)ˆ0

Answer 1

Răspuns

Explicație pas cu pas:

1-(9/8)^6 * (2/3)^12  = 1 - 3^12 * 2^12 / 2^18 * 3^12 = 1 - 1/2^6 = 1 - 1/64 = 63/64

(4/9)^10 *[(27/8)ˆ3 ]ˆ2 + (1/7)ˆ0 = 2^20/3^20 * (3^9/2^9)^2 + 1

= 2^20 * 3^18/3^20* 2^18 + 1 = 2^2/3^2 + 1 = 4/9 + 1 = 13/9