Question

1. a=(√2-1 )^2 +(√2/2 +1)^2 + (1/2-√5)(1/2+√5)
2. 
f:R-R , f(x) =mx+2
Determinati numarul real m, stiind ca punctul A(-1,1)

Answer 1

1) 2-2√2+1+2/4+√2+1+1/4-5=
aducem la acelasi numitor 4
8-8√2+4+2+4√2+4+1-20=
= -1-4√2
2) f(-1) = 1
-m+2=1
-m= -1
m=1