Question

1. a) a-5/a=6/11
b)2-radical 3+radical 2)(-3+radical 3-radical2)*(-3radical 2+2radical3)=
Dau coroana

Answer 1

a) (a-5)/a=6/11
6a=11(a-5)
6a=11a-55
5a=55
a=11

b)(2-√3+√2)(-3+√3-√2)(-3√2+2√3)=
=(-6+3√3-3√2+2√3-3+√6-2√2+√6-2)((-3√2+2√3)=
=(-11+5√3-5√2+2√6)(-3√2+2√3)=
=33√2-15√6+15×2-6√12-22√3+10×3-10√6+4√18=
=33√2-15√6+30-12√3-22√3+30-10√6+12√2=
=45√2-25√6+60-34√3