Question

1)Afla suma nr a si b,stiind ca: a) a:123=42rest122. b)6900:b=56rest 12. 2) Insumeaza numerele m,n,p,stiind ca: m= 82848 , n= de 48 de ori mai mic , p =citul numerelor m si 24. 3)Gaseste doua metode de rezolvare: 72000:5+72000:10+72000:15=?

Answer 1

1.____________________

a = 42 × 123 +122 = 5288
b = 6900 : 56 =123
a + b = 123 + 5288 = 5411

2.____________________

m = 82848
n = 82848 : 48 = 1726
p = 82848 : 24 = 3452
m + n + p = 82848 + 1726 + 3452 = 88026

3.____________________

72000:5 + 72000:10 + 72000:15 =
= 14400 + 7200 + 4800
= 26400

Answer 2

1
a = 42 × 123 +122
a=5166+122
a= 5288

6900=bx56+12
6900-12=bx56
6888=bx56
b = 6888: 56
b=123

a + b = 123 + 5288 = 5411



2.

m = 82848
n = 82848 : 48 = 1726
p = 82848 : 24 = 3452
m + n + p = 82848 + 1726 + 3452 = 88026

3.

72000:5 + 72000:10 + 72000:15 =
= 14400 + 7200 + 4800
= 21600+4800
= 26400