Question

1.Aflati masura redusa a arcelor cu masura de :
$\frac{17 \pi }{5}$
[tex]a) \frac{17 \pi }{5}
b)\frac{25 \pi }{12}
c)-\frac{ \pi }{3}
d)- \frac{2 \pi }{3} [/tex]
e) 2010 grade
f)-15 grade
h)-90 de grade

Answer 1

17π/5=2π+7π/5 =7π/5
25π /12 = 24π /12 +π /12 = 2π +π/12= π12
-π/3=2π-π/3=5π/3
-2π/3=2π-2π/3=4π/3
2010=7π/6
-15=2π-π/12=23π/12
-90=2π-π/2=3π/2