Question

1.Calculati masa a 3,96/dioxid CO2 in conditii normale.
2. Calculati numarul de moli din 34g amoniac.
3. Calculati cate molecule are 1 mol jumate de hidrogen.
4. Calculati masa moleculara a 2 moli de hidrogen.
5. Ce volum ocupa la 327°C si 100 atmosfera in 280g azot molecular.

Answer 1

1. Calculati masa a 3,96/dioxid CO2 in conditii normale.

V/Vm = m/miu(CO2)

=> m = Vxmiu(CO2)/Vm = 3,96x44/22,4 = 7,78 g

2. Calculati numarul de moli din 34g amoniac.

miu(NH3) = 17 g/mol

1 mol....... 17 g NH3

n moli ...... 34 g => n = 2 moli NH3

3. Calculati cate molecule are 1 mol jumate de hidrogen.

1 mol H2 contine..... 6,022x10^23 molecule H2

1,5 moli..................... n => n 1,5x6,022x10^23 = 9,033x10^23 molecule H2

4. Calculati masa moleculara a 2 moli de hidrogen.

miu(H2) = 2 g/mol

1 mol H2........... 2 g H2

2 moli.................. m = 4 g H2

5. Ce volum ocupa la 327°C si 100 atmosfera in 280g azot molecular.

miu(N2) = 28 g/mol

n = nr. moli = m/miu(N2) = 280/28 = 10 moli N2

PV = nRT => V = nRT/P = 10x0,082x(273+327)/100

= 4,92 L N2