Question

1. calculati masa de fier necesara obtinerii a 5 moli clorura de fier (3) in reactia cu clorul
2.calculati numarul de moli de carbon care reactioneaza cu clorul daca se obtin 10 moli CCL4
3.stiind ca s au obtinut 45 de moi clorura de aluminiu,calculati masa de aluminiu necesara in reactia cu clorul
4.daca 60 g hidrogen reactioneaza cu clorul calculati numarul de moli de acid clorhidric obtinut.

PLS HELP

Answer 1

Răspuns:

1.

MFeCl3 =56+3×35,5=162,5g/mol

m=162,5×3=812,5g

2×56g 2×162,5g

2Fe + 3Cl2 ==>2 FeCl3

xg 812,5g

x=812,5×2×56/2×162,5=calculează

2.

1mol 1mol

C   +  2 Cl 2 → CCl 4

ymoli 10moli

y=10×1/1=10moli

3.

MAlCl3=27+3×35,5=133,5f/mol

MAl=27g/mol

m=45×133,5=6.007,5gAlCl3

2×27g 2×133,5g

2Al + 3Cl2 => 2AlCl3

xg 6.007,5g

x=6.007,5×2×27/2×133,5=calculează

4.

MHCl=1+35,5=36,5g/mol

MH2=2×1=2g/mol

n=60/2=30moliH

1mol 2moli

H2 + Cl2=> 2HCl

30moli............zmoli

z=30×2/1=60moliHCl.

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