Question

1) calculati masa de glucoza continuta in 400 ml solutie de C= 0,2 M

2) Determinati cantitatea de energie degajata prin metabolizarea a 54 g de glucoza, stiind ca prin metabolizarea unui mol de glucoza se degaja 686 kcal.

Answer 1

2) 1 mol... 180 g glucoza ... 686 Kcal
     1mol.... 54g glucoza......x kcal

x= 54* 686 . 180 ---> x= 205,8 Kcal

Answer 2

1) Cm=n/VS==>n=Cm*Vs=0.2*0.4=0.08 moli C6H12O6

n=m/M==>m=n*M=0.08*180=14.4g glucoza (C6H12O6)

2) n=m/M=54/180=0.3 moli C6H12O6

1mol C6H12O6..............................686 kcal
0.3mol............................................x=205.8 kcal

MC6H12O6=180g/mol