Question

1.Calculati si scrieti rezultatul sub forma de fractie ireductibila:
c) 12,(3)*2,25-5$\frac{1}{2}$:4$\frac{2}{5}$

Answer 1

$12,(3)= \frac{123-12}{9}= \frac{111}{9}= \frac{37}{3}$
$2,25= \frac{225}{100}= \frac{9}{4}$
$5 \frac{1}{2}= \frac{5*2+1}{2}= \frac{11}{2}$
$4 \frac{2}{5}= \frac{4*5+2}{5}= \frac{22}{5}$
$12,(3)= \frac{123-12}{9}= \frac{111}{9}= \frac{37}{3} ;2,25= \frac{225}{100}= \frac{9}{4} \\ \frac{37}{3} * \frac{9}{4}= \frac{37*9}{3*4}= \frac{333}{12} = \frac{111}{4}$
$\frac{11}{2} : \frac{22}{5}= \frac{11}{2} * \frac{5}{22} = \frac{11*5}{2*22} = \frac{55}{44}= \frac{5}{4}$
$\frac{111}{4}- \frac{5}{4}= \frac{106}{4} = \frac{53}{2}=26 ,5$