Matematică, întrebare adresată de ppapapa, 9 ani în urmă

1)calculeaza
11m+4dam=?m
172km+600dam=?km
75dam+160m=?m
9km--200dam=?hm
15hm-410m=?dam
108m-52000mm=?m
1dam-280cm=?dm
3*6kjm=?hm
300dam:3=?m
522km:9=?m
7*40dm=?m
700cm-70mm=?cm
980dam-90m=?dam

2)7dm+?cm=1m
60cm+?dm=1m
40cm+?mm=1m
6dm+40cm=dm
8mm+10dm=?mm

40cm+?mm=1m
6dm+40cm=?dm
8mm+10=?mm


3)un automibil a parcurs 900 km in 3 zile stiind ca in primele doua zile a parcus 600 km iar in ultimele doua zile 500 km afla kilometri a parcurs in fiecare zi.






cat mari repede pana mine de dimineata

Răspunsuri la întrebare

Răspuns de renatemambouko
27
11m+4dam=11m+40 m=51m
172km+600dam=172km+6km=178km
75dam+160m=750 m+160m=910m
9km-200dam=90hm-20hm=70 hm
15hm-410m=150 dam-41dam=109dam
108m-52000mm=108 m-52 m=56 m
1dam-280cm=100 dm-28dm=72dm
3*6km=36km=360hm
300dam:3=100 dam=1000m
522km:9=58 km=58000m
7*40dm=280 dm=28m
700cm-70mm=700cm-7cm=693cm 
980dam-90m=980 dam-9dam=971dam

2)7dm+?cm=7dm+30cm=1m
60cm+?dm=60cm+4dm =1m
40cm+?mm=40 cm+600mm=1m
6dm+40cm=6dm+4dm=10dm
8mm+10dm=8 mm+100mm=108mm

40cm+600mm=1m
6dm+40cm=6dm+4dm=10dm



3)un automibil a parcurs 900 km in 3 zile stiind ca in primele doua zile a parcus 600 km iar in ultimele doua zile 500 km afla kilometri a parcurs in fiecare zi.

a+b+c=900
a+b=600
b+c=500
c=900-(a+b)=900-600=300 km a parcursa in a 3-a zi
b=500-300=200  km a parcursa in a 2-a zi
a=600-200=400 km a parcursa in 1 zi
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