Question

1.Cat e AB ?
A(4,5), B(4,-1)
A(-1,-3) , B(-1,-6)
2. Cel mai mic numar intreg (-3, 2] ?

3. Simplificați 6x^2-7x+2 supra 2x^2 + x - 2

Answer 1

1) AB²= (xA-xB)²+ (yA-yB)²
AB²= (4-4)² + (5+1)²=6²
AB=6

AB²= (-1+1)² + (-3+6)²=3²
AB=3

2) nr intregi din interval sunt : -2,-1,0,1,2   -> cel mai mic nr intreg este -2

3) 6x² -4x-3x+2 = 2x(3x-2) - 1(3x-2)= (3x-2) * (2x-1)
    2x² -x+4x-2=x(2x-1) + 2(2x-1)= (2x-1) * (x+2)

3x-2/x+2