Question

1)Descompuneti in factori:

a) (x-2)²-4x²=
b) x²+6x+9-y²=
c) x²+7x+6=
d) x²-5x+6=
e) x²+2x-3=
f)2x²+x-1=
g) x³+x²-16x-16=

Answer 1

rezolvările de la a și c

Answer 2

(x-2-2x)*(x-2+2x)=-(x+2)*(3x-2)
x²+6x+9-y²=(x+3)²-y=(x+3-y)*(x+3+y)
x²+4x+4+3x+2=(x+2)²+(2+3x)
x²-4x+4-x+2=(x-2)²-(x-2)=(x-2)*(x-2-1)=(x-2)*(x-3)
x²+2x+1-3-1=(x+1)²-(2)²=(x+1-2)*(x+1+2)=(x-1)*(x+3)
2x²+2x-x+1-2=(x²+2x+1)-(x²+x)-1)=(x+1)²-x(x+1)-1=(x+1)(x+1-x)-1=(x+1)-1
x³+x²-16x-16=x²(x+1)-16(x+1)=(x+1)*(x²-16)=(x+1)(x-4)(x+4)
la ex.c,d,e,f, se fac niste artificii de calcul care pastreaza neschimbat exercitiul
bafta!