Question

Cum se rezolva 2·(1020:85+205):[33·18-(50·10+23·4)]+1343:17-262

Answer 1

2 x (12+205):[594-(500+92)]+79-262=
2 x 217 :(594-592)+79-262=
434:2+79-262
217+79-262=
296-262=34
Prima data si prima data faci operatiile din paranteza rotunda,apoi paranteza patrata si in celelalte cazuri in care ai acolada o faci ultima.
In exercitii prima oara se fac puteriile nu e cazul acestui ex,apoi inmultirile,dupa impartire,apoi adunare si abia dupa scaderile.

Answer 2

2·(1020:85+205):[33·18-(50·10+23·4)]+1343:17-262
2·(40,8+205):[33·18-(500+92)]+1343:17-262
2·245,8:(33·18-592)+1343:17-262
2·245,8:(594-592)+1343:17-262
2·245,8:2+1343:17-262
491,6:2+1343:17-262
245,8+1343:17-262
245,8+79-262
324,8-262=62,8