Question

1 + i supra 2 - i + 1 - i supra 2 + i

Answer 1

Amplifici fiecare fractie cu conjugatul fiecarui numar complex de la numitor, deci cu 2+i, respectiv 2-i. Obtii:
$\frac{1+i}{2-i}+ \frac{1-i}{2+i}= \frac{(1+i)(2+i)}{2^2-i^2}+ \frac{(1-i)(2-i)}{2^2-i^2}= \frac{2+i+2i-1+2-i-2i-1}{4+1}= \frac{2}{5}$