Question

1-i supra√2 ,totul la putera 24

Answer 1

$[ \frac{1-i}{ \sqrt{2} }]^ ^{24} =[ [ \frac{1-i}{ \sqrt{2} }] ^{2}] ^{12}= [ \frac{-2i}{2} ] ^{12} = \frac{-2i}{4096} = \frac{-i}{2048}$

Answer 2

$[ \frac{1-i}{ \sqrt{2} }] ^{24} =( [ \frac{1-i}{ \sqrt{2} }]^2) ^{12}= ( \frac{1-2i+i^2}{2}) ^{12}= [\frac{1-2i-1}{2}] ^{12}=[(-i)^4]^3=1$