Question

1)Multimea A verifica simultanrelatiile: i)3 €A. ii) daca n€A atunci 4n€A iii)daca 2n+14€ A atunci n€A. Aratati ca 17 € A.
2)Aflati numarul natural a pentru care {1800-[1632:8+(1904-a)+468]:4+250}+516=2016. Urgent!!! Dau coroana raspunsului corect!!!! Cat mai repede va rog frumos!!!

Answer 1

2.
{1800-[1632:8+(1904-a)+468]:4+250}+516=2016
{1800-[204+(1904-a)+468]:4+250}=1500
[1800-(204+1904-a+468):4+250]=1500
[1800-(204+1904-a+468):4+250]=1500
[1800-(2576-a):4+250]=1500
1800-(2576-a):4=1250
(2576-a):4=1800-1250
2576-a=550x4
2576-a=2200
a=2576-2200
a=376

1.i)3∈A=>A={3}
ii)n∈A=>4n∈A
ex.n=3=>12∈A,adica,multiplii,lui,4,apartin,lui,A

iii)2n+14∈A=>n∈A
ex.n=3=>20∈A
Luam,alt,exemplu
n=0=>14∈A
n=1=>16∈A
n=2=>18∈A

=>17∉A