Question

1/n + 3/n + ... + (2n-1)/n = ?

Answer 1

=1/n(1+3+5+...+(2n-1)) = 1/n ((2n-1-1):2 + 1)((2n-1+1):2 =1/n*n*n=n
Progresie aritmetica cu ratia= 2, primul termen 1 si ultimul 2n-1.
Numarul termenilor: (2n-1-1):2 + 1 = n

Answer 2

1/n + 3/n + ... + (2n-1)/n = [1+3+5+ ... +(2n+1)]/n =n²/n=n