Question

1 pe 2[1pe 2+1pe2(1pe 2 + 1 pe 2 ×)]= 1. 1pe 2

Answer 1

1 / 2[1/ 2+1/2(1/ 2 + 1/2 ×)]= 1. 1/ 2
1 / 2[1/ 2+1/2(1/ 2 + 1/2 ×)]= 3/2
1/ 2+1/2(1/ 2 + 1/2 ×)=3/2:1/2
1/ 2+1/2(1/ 2 + 1/2 ×)=6/2
1/2(1/ 2 + 1/2 ×)=6/2-1/2
1/2(1/ 2 + 1/2 ×)=5/2
1/ 2 + 1/2 ×=5/2:1/2
1/ 2 + 1/2 ×=10/2
1/2 ×=10/2-1/2
1/2 ×=9/2

x=9/2:1/2

x=9