Question

1. Rezolvati ecuatiie in multimea numerelor naturale:
 3(x+2)-1=x+7
2. Rezolvati ecuatiile:
100x{10x[(45x-35):5+12]x2-21}+17=25 917
 Va rog ajutati-ma ca imi trebuie pe maine!!!!

Answer 1

1) 3(x+2)-1=x+7

3x + 6 - 1 = x + 7

3x - x = 7 - 6 + 1

2x = 2

x = 1


2) 100x{10x[(45x-35):5+12]x2-21}+17=25 917

100x{10x[(45x-35):5+12]x2-21} =25 917 - 17

100x{10x[(45x-35):5+12]x2-21} = 25 900

10x[(45x-35):5+12]x2-21 = 25900:100

10x[(45x-35):5+12]x2-21 = 259

10 × [(45x - 35) : 5 + 12]×2 = 259 + 21

10 × [(45x - 35) : 5 + 12]×2 = 280

(45x - 35) : 5 + 12 = 280 : 2 : 10

(45x - 35) : 5 + 12 = 14

(45x - 35) : 5 = 14 - 12

(45x - 35) : 5 = 2

45x - 35 = 2 × 5

45x - 35 = 10

45x = 10 + 35

45x = 45

x = 1