Question

1) rezolvati in multimea numerelor nat. Inecuatia :2(x+3)<307-251
2)rezolvati in multimea numerelor nat.inecuatia:2^x+1mai mic sau egal cu 16 adica

Answer 1

1) 2(x+3)<307-251
    2x+6   < 56
    2x       < 50
      x       < 25 --->> x={0,1,2,3,...,24}
2) 2^x+1<= 16
    2^x    <= 15
    2^1=2
    2^2=4
    2^3=8
    2^4=16 ---> x={0,1,2,3}

Answer 2

 1) 2(x+3) <56 =
(x+3)<56:2=
x+3<28=
x<28-3=
x<25