Question

1.Rezolvati in Q+ ecuatia: 0,8[1,(6)x-0,2(7)]=5 supra 4 x

Answer 1

$\frac{8}{10} *( \frac{15x}{9}- \frac{25}{90} )= \frac{5x}{4}$

$\frac{4}{5} * \frac{15x}{9} - \frac{4}{5} * \frac{25}{90} = \frac{5x}{4}$

$\frac{4x}{3} - \frac{2}{9}= \frac{5x}{4}$

Aducem la acelasi numitor si eliminam numitorii (n.c. 36)

48x-8=45x
48x-45x=8
3x=8

$x= \frac{8}{3}$