Question

1)Rezolvați în R ecuațiile:
2)Rezolvati în R ecuatiile:
VĂ ROG REPEDE DACĂ SE POATE! ​

Answer 1

Răspuns:

Explicație pas cu pas:

1) a) x²-2x = 0 <=> x(x-2) = 0 => x₁ = 0 ; x₂ = 2

b) x²+5x = 0 <=> x(x+5) = 0 => x₁ = 0 ; x₂ = -5

c) x²+9x = 0 <=> x(x+9) = 0 => x₁ = 0 ; x₂ = -9

d) 2x²-18x = 0 <=> 2x(x-9) = 0 => x₁ = 0 ; x₂ = 9

e) 2x²+14x = 0 <=> 2x(x+7) = 0 => x₁ = 0 ; x₂ = -7

f) 5x²-10x = 0 <=> 5x(x-2) = 0 => x₁ = 0 ; x₂ = 2

g) 18x² = 24x <=> 18x²-24x = 0 <=> 6x(3x-4) = 0 => x₁ = 0 ; x₂ = 4/3

h) 12x² = -8x <=> 12x²+8x = 0 <=> 4x(3x+2) = 0 => x₁ = 0 ; x₂ = -2/3

i) 15x² = 20x <=> 15x²-20x = 0 <=> 5x(3x-4) = 0 => x₁ = 0 ; x₂ = 4/3

a) x²-1 = 0 => x² = 1 => x₁,₂ = ±√1 =>  x₁,₂ = ±1 => x₁ = -1 ; x₂ = 1

b) x²-4 = 0 => x² = 4 =>  x₁,₂ = ±√4 =>  x₁,₂ = ±2 => x₁ = -2 ; x₂ = 2

c) x²-9 = 0 => x²=9 =>  x₁,₂ = ±√9 =>  x₁,₂ = ±3 => x₁ = -3 ; x₂ = 3

d) 4x²-9 = 0 => 4x² = 9 => x² = 9/4 =>  x₁,₂ = ±√(9/4) =>

x₁,₂ = ±3/2 => x₁ = -3/2 ; x₂ = 3/2

e) 9x²-4 = 0 => 9x² = 4 => x² = 4/9 =>  x₁,₂ = ±√(4/9) =>

x₁,₂ = ±2/3 => x₁ = -2/3 ; x₂ = 2/3

f) 16x²-1 = 0 => 16x² = 1 => x² = 1/16 =>  x₁,₂ = ±√(1/16) =>  

x₁,₂ = ±1/4 => x₁ = -1/4 ; x₂ = 1/4

g) 25x² = 36 => x² = 36/25 =>  x₁,₂ = ±√(36/25) =>  

x₁,₂ = ±6/5 => x₁ = -6/5 ; x₂ = 6/5

h) 49x² = 64 =>  x² = 64/49 => x₁,₂ = ±√(64/49)  =>  

x₁,₂ = ±8/7 => x₁ = -8/7 ; x₂ = 8/7

i) 81x² = 16 => x² = 16/81 =>  x₁,₂ = ±√(16/81) =>

x₁,₂ = ±4/9 => x₁ = -4/9 ; x₂ = 4/9