Question

1)Rezultatul calcului:[4*(15-2^2*3)+3^2]^3:(2^2^2+2^2+2^0) este:

2)scrie numerele x=[2^30^2*(2^6)^100+(32^4)^100:2^500]*2 si y=5*(3^2002-3^2001-9^1000) ca patrate de numere naturale.

VA ROG! E URGENT!!!
DAU COROANA!

Answer 1

[4*(15-2^2*3)+3^2]^3:(2^2^2+2^2+2^0) =
=[4*(15-4*3)+9]^3:(2^4+2^2+1) =
=[4*(15-12)+9]^3:(16+4+1) =
=(4*3+9)^3:21=
=(12+9)^3:21 =
=21^3:21 =
=21^2=
=441

 2) x=[2^30^2*(2^6)^100+(32^4)^100:2^500]*2 =
=[2^900*2^600+(2^20)^100:2^500]*2 =
=(2^1500+2^2000:2^500)*2 =
=(2^1500+2^1500)*2 =
=2^1500(2^0+2^0)*2 =
=2^1500*2*2 =
=2^1502=(2^751)^2

 y=5*(3^2002-3^2001-9^1000) =
=5*(3^2002-3^2001-3^2000) =
=5*3^2000*(3^2-3^1-3^0) =
=5*3^2000*(9-3-1) =
=5*3^2000*5 =
=(5*3^1000)^2