Question

1)se da a supra b =0,4,sa se afle 3b supra 2a +3b
2)daca 3b supra 2a+3b = 15 supra19,sa se afle a supra b
MERSIII DAU COROANA

Answer 1

1)
a/b= 0,4⇒a=0,4·b
3b / (2a+3b) = 3b / (2·0,4·b +3b ) = 3b/3,8b = 3/3,8 =30/38=15/19
2)
3b / (2a+3b) = 15/19
3b·19 = 15(2a+3b)
57b=30a+45b
57b-45b=30a
12b=30a
a/b=12/30
a/b=4/10=0,4