Question

1. Sodiu + clor -> 585 g sare.
? g sodiu
? moli clor

2
Aluminiu + 64 g oxigen
? Moli de aluminiu
? g produs de reactie

Answer 1

2Na + Cl2 => 2NaCl

n=m/M=585/58,5=10 moli NaCl

2*23g Na............2 moli NaCl
xg Na................10 moli NaCl

x=230g Na

1 mol Cl2...............2 moli NaCl
x=5 moli Cl2.........10 moli NaCl

2. 4Al + 3O2 => 2Al2O3

n=m/M=64/32=2 moli O2

4 moli Al....................3 moli O2
x=2,666 moli Al..........2 moli O2

3 moli O2..........2*102g Al2O3
2 moli O2............x=136g Al2O3