Matematică, întrebare adresată de Tycoon, 9 ani în urmă

1)[tex]a) \frac{3}{5} + \frac{5}{12} ; b) \frac{3}{7} + \frac{7}{10} ; c) \frac{1}{4} + \frac{7}{13} ;
d) \frac{3}{4} + \frac{7}{15} ; e) \frac{2}{5} + \frac{3}{16} ; f) \frac{4}{9} + \frac{5}{11} ; [/tex]
2) [tex]a) \frac{3}{11} + \frac{1}{10} ; b) \frac{1}{13} + \frac{1}{10} ; c) \frac{1}{17} + \frac{1}{10} ;
d) \frac{1}{19} + \frac{1}{20} ; e) \frac{1}{13} + \frac{1}{30} ; f) \frac{1}{29} + \frac{1}{10} ;[/tex]
3) a)  \frac{1}{4} +  \frac{1}{16}  +  \frac{1}{64}; b)  \frac{1}{5} +  \frac{1}{25} +  \frac{1}{125}  ;   c)   \frac{1}{6} +  \frac{1}{36} +  \frac{1}{216} ;  d)   \frac{1}{7}  +  \frac{1}{49} +  \frac{1}{343} ;

Răspunsuri la întrebare

Răspuns de iakabcristina2
3
1.
a)(3x12+5x5)/(5x12)=(36+25)/60=61/60
b)(3x10+7x7)/(7x10)=(30+49)/70=79/70
c)(1x13+4x7)/(4x13)=(13+28)/52=41/52
d)(3x15+4x7)/(4x15)=(45+28)/60=73/60
e)(2x16+3x5)/(5x16)=(32+15)/80=47/80
f)(4x11+5x9)/(9x11)=(44+45)/99=89/99

2.
a)(3x10+1x11)/(11x10)=(30+11)/110=41/110
b)(10+13)/130=23/130
c)(10+17)/170=27/170
d)(20+19)/380=39/380
e)(30+13)/390=43/390
f)(10+29)/290=39/290

3.
a)(16+4+1)/64=21/64
b)(25+5+1)/125=31/125
c)(36+6+1)/216=43/216
d)(49+7+1)/343=57/343

Tycoon: Mulțumesc!
iakabcristina2: Cu placere :)
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