Question

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1)$C_{1} =4cm$
$C_{2} =4 \sqrt{3}$
ipotenuza=?

Answer 1

$\displaystyle C_1=4~cm \\ C_2=4 \sqrt{3} ~cm \\ ip^2=C_1^2+C_2^2 \\ ip^2=4^2+(4 \sqrt{3} )^2 \\ ip^2=16+48 \\ ip^2=64 \\ ip= \sqrt{64} \\ \boxed{ip=8~cm}$