Question

1. Va roog AJUTATI-MA!!! Calculati:

Answer 1

[tex][3^{57}:(3^2)^{25}\cdot 3^{10}]:3^{15}=\\ =(3^{57}:3^{50}\cdot 3^{10}):3^{15}=\\ =3^{57-50+10}:3^{15}=\\ =3^{17}:3^{15}=\\ =3^{17-15}=3^2=9\\ \\ \\ 2\cdot 2^2\cdot 2^{43}-2^{46}+1=\\ =2^{1+2+43}-2^{46}+1=\\ =2^{46}-2^{46}+1=\\ =1[/tex]