Question

Demonstrati ca lg 4+6 supra 2 > lg 4+lg 6 supra 2

Answer 1

Din felul in care ai scris tu deduc ca exercitiul arata asa:

$\frac{lg(4+6)}{2}\ \textgreater \ \frac{lg4+lg6}{2} \\ lg10\ \textgreater \ lg24 \\ 10\ \textgreater \ 24\ Fals$