Question

1)(x+1)la patrat-(x-1)patrat

2)descompuneti in factori
xpatrat-1..
xpatrat-2x...
xpayrat-6x+8..
pls:

Answer 1

[tex](x+1)^2-(x-1)^2=[(x+1)+(x-1)][(x+1)-(x-1)]=4x\\ x^2-1^2=(x+1)(x-1)\\ x^2-2x=x(x-2)\\ x^2-6x+8=x^2-2x-4x+8=x(x-2)-4(x-2)=(x-2)(x-4)[/tex]