Question

1.(x+√3)² - (√2x + 2√3) ² =
2. 8x² - (√2x+1)² =
3. ( $\frac{3x}{5}$ - y)² - 4y²=
4. ( 2x+$\frac{1}{4}$) ² - (x -$\frac{3}{4}$) ² =
5. (3-x)²- ($\frac{3}{2}$)²=

Answer 1

1. = x² + 2√3x + 3 - ( 2x² + 4√6x + 12 )
   = x² + 2√3x + 3 - 2x² - 4√6x - 12
   = - x² + 2√3x - 4√6x - 9
2. = 8x² - ( 2x² + 2√2x + 1
   = 8x² - 2x² - 2√2x + 1
   = 6x² - 2√2x + 1
3. = 9x²/25 - 6/5xy + y² - 4y²
   = 9x² - 6/5xy - 2y²
4. = 4x² + x + 1/16 - ( x² - 3/2x + 9/16 )
   = 4x² + x + 1/16 - x² + 3/2x - 9/16
   = 3x² + x + 1,5x - 1/2
   = 3x² + 2,5x - 0,5
5. = 9 - 6x + x² - 9/4
   = x² - 6x + 9 - 2,25
   = x2 - 6x + 6,75