Question

10,04% C
Formula molec.
F. Bruta
0,83%H
89,12%Cl
(miu) = 119,5

Va rog ajutati ma Cat mai repede. Dau coroana

Answer 1

C = 10,04/12 = 0,836

H = 0,83/1 = 0,83

Cl = 89,12/35,5 = 2,51

impartim la cel mai mic multiplu comun 0,83

=>

C = 1

H = 1

Cl = 3

=> Fb = (CHCl3)n

n = M.fm/M.fb = 119,5/119,5 = 1

=> Fm = CHCl3