Question

10•{81^2:(3^2)^4+2•[(2^2•3)^15:(2^29•3^15)+1]}
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Answer 1

10× {81^2÷(3^2)^4+2×[(2^2×3)^15÷(2^29×3^15)+1]} =

= 10×[(3^4)^2:3^8×(2^30:2^29×3^15:3^15+1)] =

= 10× [3^8:3^8×(1 + 1)] =

= 10 × (1 × 2) =

= 20