Question

10. 9. 8. 16
(9. -9. -9. ):(71×3. )=? Adica: (9 la puterea 10 - 9 la puterea 9-9 la puterea 8):(71×3la puterea 16)

Answer 1

$\frac{ 9^{10}-9^9-9^8 }{71*3^{16}}= \frac{9^8(9^2-9-1)}{71*3^{16}}= \frac{(3^2)^8(81-9-1)} {71*3^{16}}= \frac{3^{16}*71}{71*3^{16}}=1$